تصحيح إختبار الفصل الأول للثالثة ثانوي 1

92143 250 2351951381 92040520 Ten 250 235 2352 235 92143 9222 Mmmm 931 1790 235 235 Vnuc 952 Zrm 8844

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06  92143 0 25 0 25 0 5  1 0 250 25 2 A 95 Z 52 2351951381 92040520 3 Un Zr Ten   0 25 X 20 5 3 0 250 25 4 0 25 0 25 0 5 5 235 92 U 40 A Zr 2352 92 L E Um C   235 92 92143 1 9222 Pn Mmmm U Mu        931 5 1790 53 L L Em E Me V     235 92 7 72 235 L EU Me Vnuc 952 40 L E Zrm C   0 8844 Mu 823 82 L E Me V 95 40 8 67 95 L E Zr Me V 95 40 Zr 235 92 U 0 25 0 25 0 25 0 25 01 6 M 13895235 524092 3 0 1893 Nn Mmm Tem Zrm Um Mu          0 25 0 25 0 5 7 Lib E 235 176 33 Lib Lib Emc E Me V     0 25 0 25 8 23 21 1 6 02 10 235 2 56 10 A M NN M N Nnoy      23 4 52 10 L Tlib LT ENE E Me V   0 25 0 25 0 25 0 75 9 0 50 5 100 E T E E  E Et 7 24 3600 604800 T Ts     6 13 25 20 10604800 1 2096 10 7 56 10 E E E E EJ E Me V      100 T E 30 E E 26 2 52 10 T E Me V 23 26 14 52 10 2 52 10 T G Me

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